We have the next inequality
[tex]3x+8<-1[/tex]And we must find its solutions
1. We must substract 8 from both sides
[tex]\begin{gathered} 3x+8-8<-1-8 \\ 3x<-9 \end{gathered}[/tex]2. We must divide both sides by 3
[tex]\begin{gathered} \frac{3x}{3}<-\frac{9}{3} \\ x<-3 \end{gathered}[/tex]ANSWER:
[tex]x<-3[/tex]