Fractional part of battery: B
t: hours
[tex]B=5^{-0.02t}[/tex]
After 50 hours of use:
Substitute the t in the equation by 50 and evaluate:
[tex]\begin{gathered} B=5^{-0.02(50)} \\ \\ B=5^{-1} \\ \\ B=\frac{1}{5^1} \\ \\ B=\frac{1}{5} \end{gathered}[/tex]Then, 1/5 of the battery is still operating after 50 hours of use
