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Supposed to mean income of firms in the industry for year is $85 million with a standard deviation of $9 million. If incomes for the industry are distributed normally what is the probability that a randomly selected firm will earn less than $105 million? Round answer to four decimal places

Supposed to mean income of firms in the industry for year is 85 million with a standard deviation of 9 million If incomes for the industry are distributed norma class=

Respuesta :

Given[tex]Z=\frac{x-\mu}{\sigma}[/tex][tex]\begin{gathered} x=105miliion \\ \mu=85\text{ million} \\ \sigma=9\text{ million} \end{gathered}[/tex][tex]\begin{gathered} Z=\frac{105-85}{9} \\ \\ Z=2.22222 \end{gathered}[/tex]

Now

The final answer[tex]0.9869\text{ \lparen4 d. p\rparen}[/tex]

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