Answer:
AM = 36, AB = 72
MN = 9, AC = 18
Explanation:
Solving the equations of the previous problem, we find that x = 9 and y = 6.
Now we put these values in the expressions for the side lengths and find the length measures.
[tex]AM=5x-9[/tex]putting in x = 9 gives
[tex]\begin{gathered} AM=5(9)-9 \\ AM=36 \end{gathered}[/tex]For AB we have
[tex]\begin{gathered} AB=(5x-9)+(2x+18) \\ \end{gathered}[/tex]putting in x = 9 gives
[tex]\begin{gathered} AB=(5(9)-9)+(2(9)+18) \\ AB=72 \end{gathered}[/tex]For MN we have
[tex]MN=y+3[/tex]putting in y = 6 gives
[tex]\begin{gathered} MN=6+3 \\ MN=9 \end{gathered}[/tex]which is our answer!
For AC we have
[tex]AC=7y-24[/tex]putting in y = 6 gives
[tex]\begin{gathered} AC=7\cdot6-24 \\ AC=18 \end{gathered}[/tex]Hence, to summarise
AM = 36, AB = 72
MN = 9, AC = 18
