FleurN326617 FleurN326617

29-10-2022
Mathematics

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find the open interval where the function f(x)= 1/3 x^3 -3x^2+5x-7 is concave down

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OlliverU614126 OlliverU614126

29-10-2022

SOLUTION

Concavity interval definitions is given as

If f"(x) > 0, then f(x) concave upwards

If f"(x) < 0, then f(x) concave downwards

[tex]f^{\prime}^{\prime}(x)=2x-6[/tex]

equating to zero, we have

[tex]concave\text{ }downward:-\inftyso, cocave downwards becomes [tex]-\infty

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