SharvaP515387
SharvaP515387
29-10-2022
Mathematics
contestada
24 square root of 2 ,45 degrees find x
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DaylaniI242877
DaylaniI242877
29-10-2022
Let's use cos identity:
[tex]\begin{gathered} \cos (\theta)=\frac{adjacent}{\text{hypotenuse}} \\ So\colon \\ \cos (45)=\frac{x}{24\sqrt[]{2}} \\ \text{Solving for x:} \\ (24\sqrt[]{2})\cdot\cos (45)=x \\ x=24^{\circ} \end{gathered}[/tex]
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