Given:
There is a equation given as
[tex]x^2-12x+32=0[/tex]Required:
We need to solve the given equation by factorization
Explanation:
By factorization
[tex]\begin{gathered} x^2-12x+32=0 \\ x^2-8x-4x+32=0 \\ x(x-8)-4(x-8)=0 \\ (x-4)(x-8)=0 \\ x=4,8 \end{gathered}[/tex]Final answer:
x=4,8
