The M&M bag has
R: 178 red colored candy
B: 154 blue colored candy
Y: 122 yellow colored candy
G: 93 green colored candy
The total number of candies in the bag are
[tex]178+154+122+93=547[/tex]To calculate the probability for each colour you have to divide the number of candies of each colour by the total number of candies in the bag
[tex]P(R)=\frac{178}{547}[/tex][tex]P(B)=\frac{154}{547}[/tex][tex]P(Y)=\frac{122}{547}[/tex][tex]P(G)=\frac{93}{547}[/tex]You have to calculate the probability of chosing three yellow candies:
[tex]P(Y_{}\cap Y\cap Y)=P(Y)\cdot P(Y)\cdot P(Y)=3P(Y)=3\cdot(\frac{122}{547})=\frac{366}{547}[/tex]As percent
[tex]\frac{366}{547}\cdot100=66.91[/tex]It is 66.91%
