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During last Friday night's football game, a total of 250 hamburgers and sodas were sold totaling $368. If each hamburger, x, costs $2 and each soda, y, cost $1, what was the number of hamburgers sold? 368

Respuesta :

Let x be the number of hamburger

Let y be the number of soda

If a total of 250 hamburgers and soda were sold, then,

This implies

x + y = 250 ----------------------------(1)

If each hamburger costs $2 and each soda costs$1 and the total cost is $368

Then, this implies;

2x + y = 368 -----------------------------(2)

Let's now solve the two equation simultaneously

Using the elimination method, we will eliminate y

Subtract equation(1) from equation(2)

x = 118

Therefore, the number of hamburger sold is 118

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