Let the charge be y($) and the number of miles driven be m;
For company A;
[tex]y=80[/tex]For company B;
[tex]y=60+0.60m[/tex]When the charge of company A is less than company B, we have;
[tex]80<65+0.6m[/tex]So, we solve the inequality as;
[tex]\begin{gathered} 80-65<0.6m \\ 0.6m>15 \\ m>\frac{15}{0.6} \\ m>25 \end{gathered}[/tex]When the milleage is greater than 25miles, the charge of company A is less than company B