Solution:
Given the circle;
[tex]|OF|\cong|OE|=r[/tex]
Thus;
[tex]\triangle FOE\text{ is isosceles triangle}[/tex]
Then;
[tex]\begin{gathered} \angle OFE=38^o \\ \\ \angle Arc\text{ }DF=38^o+38^o..............(\text{ An exterior angle of a triangle is equal to the sum of the two interior opposite angles\rparen} \\ \\ \angle Arc\text{ }DF=76^o \end{gathered}[/tex]
CORRECT OPTION: B
