RioG51022
RioG51022
29-10-2022
Mathematics
contestada
I need help. I'll send a pic :)
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IeshaU675578
IeshaU675578
29-10-2022
[tex]\begin{gathered} So,\text{ the angle }\angle Q=\angle R \\ 2x+38=180^{\circ} \\ 2x=142^{\circ} \\ x=71^{\circ} \\ So,\text{ the exterior anle at Q is } \\ \Rightarrow180^{}-71^{\circ} \\ \Rightarrow109^{\circ} \end{gathered}[/tex]
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