The electric field between two parallel plates is given by the equation:
[tex]E=\frac{V}{d}[/tex]where V is the difference of potential and d is the distance between the plates. In this case the difference of potential is 59.98 V and the distance between the plates is 2.17 mm, then we have:
[tex]\begin{gathered} E=\frac{59.98}{2.17\times10^{-3}} \\ E=2.76\times10^4 \end{gathered}[/tex]Therefore, the electric field is:
[tex]E=2.76\times10^4\text{ }\frac{N}{C}[/tex]