KalyF472672
KalyF472672
30-10-2022
Mathematics
contestada
2y+12 greater than or equal to 42
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MayzieU762322
MayzieU762322
30-10-2022
[tex]\begin{gathered} 2y+12\ge42 \\ 2y\ge42-12 \\ 2y\ge30 \\ y\ge\frac{30}{2} \\ y\ge15 \end{gathered}[/tex]
Then, the solution of the inequality is:
[tex]y\ge15[/tex]
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