The relation between the force, test charge and electric field is,
[tex]E=\frac{F}{q}[/tex]where F is the force, q is the charge and E is the electric field.
Substituting the known values,
[tex]\begin{gathered} E=\frac{245}{1.93} \\ E=126.94NC^{-1} \end{gathered}[/tex]Thus, the value of the magnitude of the electric field is 126.94 newton per coulomb.
