A figure is made up of a triangle and a rectangle. The trianglehas a height of 6.5 inches and a base of 11 inches. Therectangle has dimensions of 9 inches x 11 inches. What isthe total area of the figure?

Answer:
d. 134.75 square inches
Explanation:
Given:
For Triangle:
Height = 6.5 inches
Base = 11 inches
For Rectangle:
Dimensions = 9 inches x 11 inches
First, calculate the area of triangle. We use the formula:
[tex]\begin{gathered} A=\frac{bh}{2} \\ \text{where:} \\ b=\text{base} \\ h=\text{height} \end{gathered}[/tex]We plug in what we know.
[tex]\begin{gathered} A=\frac{bh}{2} \\ =\frac{(11)(6.5)}{2} \\ \text{Calculate} \\ A=35.75in^2 \end{gathered}[/tex]Next, we calculate the area of the rectangle. We use the formula:
A= lw
where:
l=length
w=width
So,
A=lw
=(9)(11)
Calculate
A = 99 in^2
The last step is to add the two areas together.
Total Area = Area of Triange + Area of Rectangle
= 35.75 in^2 + 99 in^2
= 134.75 in^2
Therefore, the total area is 134.75 square inches.