Given:
[tex]z=8(\cos (240)+i\sin (240))[/tex]
Solution:
[tex]\begin{gathered} z=8(\cos (240)+i\sin (240)) \\ z=8\cos (240)+i8\sin (240) \end{gathered}[/tex][tex]\begin{gathered} \cos (240)=-0.5 \\ \sin (240)=-0.866 \end{gathered}[/tex][tex]\begin{gathered} z=8\cos (240)+i8\sin (240) \\ =8(-0.5)+i8(-0.866) \\ =-4+i(-6.9) \\ =-4-i6.9 \\ =-4-6.9i \end{gathered}[/tex]
