The direction of the resultant force on the ball = 28.3°
Explanation:Sue's foot exerts a force of 28.85 N East
Jenny's foot exerts a force of 15.53 N North
This can be represented diagrammatically as:
The magnitude of the resultant force, R, is calculated using the Pythagora's theorem
[tex]\begin{gathered} R^2=28.85^2+15.53^2 \\ R=\sqrt[]{28.85^2+15.53^2} \\ R=32.76N \end{gathered}[/tex]The resultant force on the ball is 32.76N
The direction of the resultant force is given as:
[tex]\begin{gathered} \theta\text{ =}\tan ^{-1}\text{ }\frac{15.53}{28.85} \\ \theta\text{ =}\tan ^{-1}\text{ }0.5383 \\ \theta=28.3^0 \end{gathered}[/tex]The direction of the resultant force on the ball = 28.3°