Starting with the expression:
[tex]-16x=2y-5[/tex]Isolate y to write the expression in slope-intercept form:
[tex]\begin{gathered} \Rightarrow5-16x=2y \\ \Rightarrow2y=5-16x \\ \Rightarrow y=\frac{5}{2}-8x \\ \Rightarrow y=-8x+\frac{5}{2} \end{gathered}[/tex]Therefore, the slope-interept form of this equation, is:
[tex]y=-8x+\frac{5}{2}[/tex]