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Scores on a dental anxiety range from 0 (no anxiety) to 20 (extreme anxiety). The scores are normally distributed with a mean of 11 and a standard deviation of 4. Find the z-score for the score of 17 on this dental anxiety scale. Round to the nearest hundredth.

Respuesta :

For a normal distribution, we have the mean μ and the standard deviation σ:

[tex]\begin{gathered} \mu=11 \\ \sigma=4 \end{gathered}[/tex]

The z-score can be calculated using the formula:

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

Where X is a score from the normal distribution. For X = 17, we have:

[tex]\begin{gathered} Z=\frac{17-11}{4}=\frac{6}{4} \\ \\ \therefore Z=1.5 \end{gathered}[/tex]

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