We have the equation:
[tex]4x+25=9+2\cdot(3x+3)[/tex]We can isolate x:
[tex]\begin{gathered} 4x+25=9+6x+6 \\ 4x+25=15+6x \\ 4x-6x=15-25 \\ -2x=-10 \\ x=\frac{-10}{-2}=5 \end{gathered}[/tex]The solution is x=5.
Now we will subtitute x=5 in the equation to check the solution is ok:
[tex]\begin{gathered} \text{The equation:} \\ 4x+25=9+2\cdot(3x+3) \\ \text{The solution x=5, so replace the value of x:} \\ 4\cdot5+25=9+2\cdot(3\cdot5+3) \\ 20+25=9+2\cdot(15+3_{}) \\ 45=9+2\cdot18 \\ 45=9+36 \\ 45=45 \end{gathered}[/tex]The solution is OK
