Respuesta :

SOLUTION

The divison is:

[tex]\frac{x^4-x^2}{x-1}[/tex]

The quotient is:

[tex]\begin{gathered} \frac{x^2(x^2-1)}{x-1} \\ =\frac{x^2(x-1)(x+1)}{x-1} \\ =x^2(x+1) \end{gathered}[/tex]

Notice that there is no remainder

Hence the answer is:

[tex]0[/tex]

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