7 choco chip
9 peanut butter
8 sugar
8 oatmeal
--------------
total = 32 cookies
We want probabilty of selecting peanut butter and then oatmeal (given he eats the peanut butter).
Prob of peanut butter is 9/32
Then,
we are left with 31 cookies (since ate 1)
we still have 8 oatmeal, so
Prob of oatmeal 8/31
Now we mutliply:
[tex]\frac{8}{31}\times\frac{9}{32}=\frac{9}{124}[/tex]This is the final answer, reduced. (9/124)
