Respuesta :
First we must calculate the current power the curling iron can handle:
[tex]P=I\times V[/tex]where
I = current
V = tension
Then:
[tex]\begin{gathered} 600=I\times120 \\ I=5A \end{gathered}[/tex]For the hair dryer we get:
[tex]\begin{gathered} P=I\times V \\ 1200=I\times120 \\ I=10A \end{gathered}[/tex]Lets suppose all appliances are working in parallel together. The total current must be:
[tex]\begin{gathered} I=I_1+I_2 \\ I=5+10 \\ I=15A \end{gathered}[/tex]As we can see the appliances are drawning all current from the outlet fused.
Answer: the current that can be safely drawn from the outlet fused is zero.
