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0.500 mol of air are held in a 3.49 L flask. What is the pressure of the air if the temperature of the flask is 310.0 K?A) 4.23B) 4.12C) 3.65D) 3.94

Respuesta :

According to the explanation given in the previous session, we have another situation in which we will be using the Ideal gas law formula:

PV = nRT

P = ?

V = 3.49 L

n = 0.500 moles

R = 0.082

T = 310 K

Now we add these values into the formula

P * 3.49 = 0.500 * 0.082 * 310

3.49P = 12.71

P = 3.65 atm, letter C

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