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Claim: Most adults would ease all of their personal information online if they could. A software firm survey of 693 randomly selected adults showed that 58% of them would orase all of their personal information onlineif they could. Find the value of the test statisticThe value of the test statistics(Round to two decimal places as needed)

Respuesta :

Data:

P: sample proportion

p0: hypothesis proportion

n: sample size

P: 58% = 0.58

p0: >50% (most adults)= 0.5

n:693

To find the value of the test statistic you use the next formula:

[tex]z=\frac{P-p0}{\sqrt[]{\frac{p0(1-p0)}{n}}}[/tex]

Then you get:

[tex]z=\frac{0.58-0.5}{\sqrt[]{\frac{0.5(1-0.5)}{693}}}[/tex][tex]z\approx4.21[/tex]Then, the value of the test statistic is approx. 4.21

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