[tex]Recursive\text{ rule tells us that a}_{n+1}\text{ = a}_n+d[/tex]
We are given the formula f(n) = f(n-1) + 5 for n larger than and including 1.
f(1) = f(0) + 5 = 1
f(2) =f(1) + 5 = 6
f(3) = 11
f(4) = 16
f(5) = 21
f(6) = 26
For an arithmetic sequence:
[tex]\begin{gathered} a_n\text{ = a +\lparen n-1\rparen d} \\ a_{n\text{ = 1 +\lparen n-1\rparen5}} \end{gathered}[/tex]
explicit rule: Tn = 1 +(n-1)5
