Total number of books = 12
[tex]P\mleft(history\mright)=\frac{5}{12}[/tex]since one book has been taken
[tex]P\mleft(animals\mright)=\frac{4}{11}[/tex]The probability is then the product of both probabilities, that is:
[tex]P\mleft(historyandanimals\mright)=\frac{5}{12}\times\frac{4}{11}[/tex]Solving we get:
[tex]P\mleft(historyandanimals\mright)=\frac{20}{121}[/tex]