Given:
It is given that
[tex]\begin{gathered} \theta\text{ = 60}^0 \\ Arc\text{ length = 14}\pi \end{gathered}[/tex]
Required:
The radius of the circle
Explanation:
The length of an arc is given by the formula,
[tex]\begin{gathered} Arc\text{ length = }\frac{\theta}{360}\text{ }\times\text{ 2}\pi r \\ \end{gathered}[/tex]
Substituting the values in the formula,
[tex]\begin{gathered} 14\pi\text{ = }\frac{60}{360}\text{ }\times\text{ 2}\times\pi\times r \\ r\text{ = }\frac{14\times360}{60\times2} \\ r\text{ = }\frac{5040}{120} \\ r\text{ = 42} \end{gathered}[/tex]
Answer:
Thus the radius of the circle is 42 m.
