Take into account that the area of a rectangular shape, is given by the following formula:
A = l·w
w: width = ?
l: length = 1 4/5 in
A: area = 33/20 in²
In order to determine the width of the photo, solve the previous formula for w:
w = A/l
convert 1 4/5 to a normal fraction:
1 4/5 = (5 + 4)/5 = 9/5
replace the values of A and l into the expression for w:
w = (33/20)/(9/5)
w = 165/180
simplify the previos fraction:
w = 165/180 = 33/36 = 11/12
Hence, the width of the photograp is 11/12 in
