Respuesta :

The problem can be solved as follows:

[tex]\begin{gathered} \ln (5x+6)=3 \\ \log _e(5x+6)=3 \\ 5x+6=e^3 \\ x=\frac{e^3-6}{5} \end{gathered}[/tex]

So the value of x is:

[tex]x=\frac{e^3-6}{5}\approx2.8171[/tex]

So the apprximate value of x is 2.8171.