height = 20 inches
radius of the cone = 6 inches
Therefore,
[tex]\begin{gathered} \text{volume}=\frac{1}{3}\pi r^2h \\ \text{volume}=\frac{1}{3}\times\pi\times6^2\times20 \\ \text{volume}=\frac{1}{3}\times\pi\times36\times20 \\ \text{volume}=\frac{720\pi}{3} \\ \text{volume}=240\pi^{}inches^3 \end{gathered}[/tex]