Given:
The initial distance is
[tex]x_0=-20\text{ m}[/tex]The initial velocity is
[tex]v_0=\text{ 0m /s}[/tex]The acceleration is a = 5 m/s^2.
The time interval is t = 10 s.
To find the final position, x.
Explanation:
The final position can be calculated as
[tex]\begin{gathered} x=x_0+v_0t+\frac{1}{2}at^2 \\ =-20+0\times10+\frac{1}{2}\times5\times(10^)^2 \\ =230\text{ m} \end{gathered}[/tex]Thus, the final position is 230 m
