Given the equation:
[tex]\bar{x}=\frac{x_1+x_2+x_3+x_4+x_5}{n}[/tex]
In this question:
x- = 85.6
x₁ = 78
x₂ = 92
x₃ = 94
x₄ = 80
x₅ = missing
n = 5
Substitute the values and then solve for x₅.
[tex]\begin{gathered} 85.6=\frac{78+92+94+80+x_5}{5} \\ 85.6=\frac{344+x_5}{5} \\ \text{ Multiplying both sides by 5:} \\ 85.6*5=\frac{344+x_5}{5}*5 \\ 428=344+x_5 \\ \text{ Subtracting 344 from both sides:} \\ 428-344=344-344+x_5 \\ 84=x_5 \end{gathered}[/tex]
Answer: 84.
