the acceleration is 0.6 m/s^2
Explanation
the acceleration of an object is given by
[tex]\begin{gathered} a=\frac{v_f-v_i}{t} \\ where \\ a\text{ is the acceleration} \\ v_f\text{ is the final velocity} \\ v_i\text{ is the initial velocity} \\ t\text{ is the time taken} \end{gathered}[/tex]so
Step 1
a)let
[tex]\begin{gathered} initial\text{ velocity=v}_i=12\frac{m}{s} \\ final\text{ velocity =21}\frac{m}{s} \\ time\text{ = 15 seconds} \end{gathered}[/tex]b) now, replace in the formula
[tex]\begin{gathered} a=\frac{v_{f}-v_{i}}{t} \\ a=\frac{21\frac{m}{s}-12\frac{m}{s}}{15s} \\ a=\frac{9\frac{m}{s}}{15\text{ s}} \\ a=0.6\frac{m}{s^2} \\ \end{gathered}[/tex]therefore, the acceleration is 0.6 m/s^2
I hope this helps you