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Calculate the [H*] for(a) pure water(b) lemon lime soda with a pH of 4.3(C) root beer with a pH of 5.8(d) window cleaner with a pH of 10.3

Respuesta :

[tex]\begin{gathered} pH\text{ = - }\log _{10}\text{ }\lbrack H^+\rbrack\text{ (1)} \\ \lbrack H^+\rbrack=10^{-pH}\text{ (2)} \end{gathered}[/tex]

a) Pure water:

pH = 7 ==> we use (2)

[tex]\lbrack H^+\rbrack=10^{-7}\text{ M (mol/L)}[/tex]

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