Given:
The peak electric field strength is: E = 115 V/m
To find:
The intensity of an electromagnetic wave.
Explanation:
The intensity of an electromagnetic wave in terms of electric field intensity is given as:
[tex]I=\frac{c\epsilon_0E^2}{2}[/tex]Here, I = Intensity of an electromagnetic wave
c = The speed of light in a vacuum
ε₀ = The permittivity of free space
Standard data:
c = 3 × 10⁸ m/s
ε₀ = 8.854 × 10⁻¹² C²/N.m²
Substituting the values in the above equation, we get:
[tex]\begin{gathered} I=\frac{3\times10^8\text{ m/s}\times8.854\times10^{-12}\text{ C}^2\text{/N.m}^2\times115\text{ V/m}}{\text{ }2} \\ \\ I=17.56\text{ W/m}^2 \end{gathered}[/tex]Final answer:
The intensity of an electromagnetic wave is 17.56 W/m².
