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Find the area under the standard normal curve to the left of z=-0.89 and to the right of z= 2.56Round your answer to four decimal places of necessary

Respuesta :

We want to find

P(z < - 0.89 U z > 2.56)

= P(z < - 0.89) + P(z > 2.56)

P(z > 2.56) = 1 - P(z ≤ 2.56)

From the normal distribution table, the area to the left of z = - 0.89 = 0.1867

Thus,

P(z < - 0.89) = 0.1867

From the normal distribution table, the area to the left of z = 2.56 = 0.9948

P(z > 2.56) = 1 - 0.9948 = 0.0052

Thus,

P(z < - 0.89 U z > 2.56) = 0.1867 + 0.0052

P(z < - 0.89 U z > 2.56) = 0.1919

The area is 0.1919

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