ChristophN292244 ChristophN292244

31-10-2022
Mathematics

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f m∠DFC=(6b−18)°, find b so that FC−→−⊥FD−→−.I'm confused i know that its a 90 degree but i dont know where to plug the numbers

f mDFC6b18 find b so that FCFDIm confused i know that its a 90 degree but i dont know where to plug the numbers class=

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NareI654555 NareI654555

31-10-2022

Given:

[tex]\angle DFC=(6b-18)^{\circ}[/tex]

FC perpendicular to FD.

[tex]\begin{gathered} \angle DFC=90^{\circ} \\ (6b-18)^{\circ}=90^{\circ} \\ 6b=90+18 \\ 6b=108 \\ b=18 \end{gathered}[/tex]

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