Given:
[tex](x+y)^8[/tex]
We will write the first four terms of the expansion.
the general rule of the expansion is as follows:
[tex](x+y)^n=x^n+n*x^{n-1}*y+...+nCr*x^{n-r}*y^r+...+y^n[/tex]
So, the answer will be, the first four terms are:
[tex]x^8+8x^7y+28x^6y^2+56x^5y^3[/tex]
