y = 5 - 7x^2
slope of the curve = derivative of y' = -14x
At the point P(4, -107) the slope is:
y' = -14(4) = -56
a) Answer: Slope at P(4, -107) is -56
b) The equation would be:
y = mx + b where m = -56 and we can calculate b using the point: (4, -107)
b = y - mx = -107 - (-56)(4) = -107 + 224 = 117
b) Answer: Equation of the tangent line at P is
y = -56x + 117
