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A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping. Part A What was the initial speed of the bullet? Express your answer with the appropriate units. μΑ ? V = Value

Respuesta :

The initial speed of the bullet before getting embedded into the wooden block is 0.39 m/s.

The mass of the bullet is 3 grams and it is embedded into the wooden block of mass 1.20 Kg.

The coefficient of friction between the block and the surface of block is 0.20. The bullet remains embedded into the block when it slides till 0.390m along the surface before stopping.

We know,

Work done by resistive force = Change in kinetic energy.

Resistive force = 0.009 x 0.20 x 0.390

Putting values,

0.009 x 0.20  x 0.390 = 0.5 x 0.009 x V²

V is the initial speed of the bullet.

V = 0.39 m/s.

The initial speed of the block is 0.39 m/s.

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