Answer with Step-by-step explanation:
The nth term A(n) of the arithmetic progression is calculated by:
A(n)=A(1)+(n-1)d
where d is the common difference
d=A(n)-A(n-1)
Here, we are given an arithmetic progression:
15,13,11,9,...
d=A(2)-A(1)
=13-15
= -2
A(10)=A(1)+(10-1)(-2)
= 15+9(-2)
Hence, equations which could be used to solve for the tenth term of the sequence 15, 13, 11, 9, ... is:
A(10) = 15 + 9(-2)
