itslilnv1
itslilnv1
28-03-2015
Mathematics
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(3+5)x7-[10+(45-15)\5]
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Аноним
Аноним
28-03-2015
[tex]Use\ PEMDAS\\\\(3+5)\times7-[10+\frac{(45-15)}{5}]=(8)\times7-(10+\frac{30}{5})\\\\=56-(10+6)=56-16=\boxed{\boxed{40}}[/tex]
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