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27-05-2017
Mathematics

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(y-7)(y+3)<(y-3)(y+3)

Respuesta :

27-05-2017

If you work out both sides, you get:

y^2 - 4y - 21 < y^2 - 9
-4y < 12
y > -3 (remember, if you divide by a negative number, the less-than flips and becomes a greater than)

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