alright we consider 3 cases 1. where the absolute value is less than 0 2. where the absolute value is equal to 0 3. where the aboslute value is greater than 0
where is it equal to 0? |2x-4|=0 2x-4=0 2x=4 x=2
at x=2 is the important point
so we have a piecewise function f(x)=(-1)3a(2x-4)-ax for x<2 f(x)=-ax for x=2 f(x)=3a(2x-4)-ax for x>2
so take the dervitivive of each
f(x)=(-1)3a(2x-4)-ax for x<2 -7ax+12a f'(x)=-7a for x<2
f(x)=-ax for x=2 f'(x)=-x for x=2 but wait, it changes derivitives at that opint so the dervitive ther is undefined
