xorenee3
xorenee3
30-09-2017
Mathematics
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i^89 simplified. Complex number.
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alphabetsam
alphabetsam
30-09-2017
This problem can be simplified by remembering that since [tex]i= \sqrt{-1} [/tex], we have [tex]i^{4}=(-1)^{2}=1[/tex]. Then we have [tex]i^{89}=i^{88+1}=i^{88}i^{1}=(i^{4})^{22}i=(1)^{22}i=i[/tex].
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