Respuesta :

The answer is choice D. The work shown below shows why this is the case.

[tex]\sqrt[5]{224x^{11}y^8} = \sqrt[5]{32*7*x^5*x^5*x*y^5*y^3}[/tex]

[tex]\sqrt[5]{224x^{11}y^8} = \sqrt[5]{32}*\sqrt[5]{7}*\sqrt[5]{x^5}*\sqrt[5]{x^5}*\sqrt[5]{x}*\sqrt[5]{y^5}*\sqrt[5]{y^3}[/tex]

[tex]\sqrt[5]{224x^{11}y^8} = 2*\sqrt[5]{7}*x*x*\sqrt[5]{x}*y*\sqrt[5]{y^3}[/tex]

[tex]\sqrt[5]{224x^{11}y^8} = 2x^2y*\sqrt[5]{7xy^3}[/tex]
Answer: Fourth option. Please see the attached file.
Thanks.
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