89df8dsf
89df8dsf
01-05-2018
Mathematics
contestada
Second Geometry B question!
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Аноним
Аноним
01-05-2018
Let the length of the radius be x.
Area of the square = 4x²
Area of the circle = πx²
Area of the unshaded = 4πx² - πx² = x² (4 - π)
[tex]\text{P(unshaded)} = \dfrac{ x^2(4- \pi )}{4x^2} = \dfrac{4- \pi }{4} = 20\% [/tex]
Answer: About 20%
Answer Link
chynajohnson1
chynajohnson1
14-10-2018
Answer: Option D.) About 20%
Answer Link
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